0.1x^2+2.4+25=500

Solution for 0.1x^2+2.4+25=500 equation:

0.1x^2+2.4+25=500

We move all terms to the left:

0.1x^2+2.4+25-(500)=0

We add all the numbers together, and all the variables

0.1x^2-472.6=0

a = 0.1; b = 0; c = -472.6;
Δ = b2-4ac
Δ = 02-4·0.1·(-472.6)
Δ = 189.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{189.04}}{2*0.1}=\frac{0-\sqrt{189.04}}{0.2}
=-\frac{\sqrt{}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{189.04}}{2*0.1}=\frac{0+\sqrt{189.04}}{0.2}
=\frac{\sqrt{}}{0.2}
$